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Given: E(Zn^(+2)//Zn)^(@) =- 0.76V E...


Given:
`E_(Zn^(+2)//Zn)^(@) =- 0.76V`
`E_(Cu^(+2)//Cu)^(@) = +0.34V`
`K_(f)[Cu(NH_(3))_(4)]^(2+) = 4 xx 10^(11)`
`(2.303R)/(F) = 2 xx 10^(-4)`
At what concentration of `Cu^(+2)` emf of the cell will be zero (at 298K) and concentration of `Zn^(+2)` is remains same:

A

`1.19xx10^(-37)`

B

`1.19xx10^(-20)`

C

`3.78xx10^(-4)`

D

`0.0068`

Text Solution

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The correct Answer is:
A
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