Redox reactions play a pivotal role in chemistry and biology. The values standard redox potential `(E^(c-))` of two half cell reactions decided which way the reaction is expected to preceed. A simple example is a Daniell cell in which zinc goes into solution and copper sets deposited. Given below are a set of half cell reactions `(` acidic medium `)` along with their `E^(c-)(V` with respect to normal hydrogen electrode `)` values. Using this data, obtain correct explanations for Question.
`I_(2)+2e^(-) rarr 2I^(c-)," "E^(c-)=0.54`
`Cl_(2)+2e^(-) rarr 2Cl^(c-), " "E^(c-)=1.36`
`Mn^(3+)+e^(-) rarr Mn^(2+), " "E^(c-)=1.50`
`Fe^(3+)+e^(-) rarr Fe^(2+)," "E^(c-)=0.77`
`O_(2)+4H^(o+)+4e^(-) rarr 2H_(2)O, " "E^(c-)=1.23`
Among the following, identify the correct statement.
(a)Chloride ion is oxidized by `O_(2)`.
(b)`Fe^(2+)` is oxidized by iodine.
(c)Iodide ion is oxidized by chlorine
(d)`Mn^(2+)` is oxidized by chlorine.

Options

A. Chloride ion is oxidised by `O_(2)`
B. `Fe^(2+)` is oxidised by iodine
C. Iodine ion is oxidised by chlorine
D. `Mn^(2+)` is oxidised by chlorine

Answer

C

Explanation

`Cl_(2)+2I^(-)toI_(2)+2Cl^(-)`
`E^(@)=1.36+(-0.54)=0.82V(+ve)`. Spontaneous.