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Consider the following cell reaction 2...

Consider the following cell reaction
`2Fe_((s))+O_(2(g))+4H_((aq.))^(o+)rarr2Fe_((aq.))^(+2)+2H_(2)O_((l))" "E^(@)=1.67V`
At `[Fe^(+2)]=10^(-3)M, P(O_(2))=0.1" atm and pH = 3, the cell potential at "25^(@)C` is …….
Use `(2.303RT)/(F)=0.059`

A

`1.47 V

B

1.77 V

C

1.87 V

D

1.57 V

Text Solution

Verified by Experts

The correct Answer is:
D
`E=E^(@)-(0.059)/(4)log([Fe^(2+)]^(2))/([H^(+)]^(4)P_(O_(2)))`
`=1.67-(0.06)/(4)log(((10^(-3))^(2))/((10^(-3))^(4)xx0.1))=1.67-(0.03)/(2)log10^(7)`
`=1.67-(0.03)/(2)xx7=1.67-0.105=1.565=1.57V`
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