Molar concentration of 96 g of `O_(2)` contained in a 2 L vessel is:

Options

A. (A) `16mol//litre`
B. (B) `1.5mol//litre`
C. (C) `4 mol//litre`
D. (D) `24 mol//litre`

Explanation

To find the molar concentration of 96 g of \( O_2 \) contained in a 2 L vessel, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Formula for Molar Concentration:**
The molar concentration (C) is defined as the number of moles (N) of solute per unit volume (V) of solution. The formula is:
\[ C = \frac{N}{V} \]
where:
- \( C \) is the molar concentration in moles per liter (mol/L),
- \( N \) is the number of moles,
- \( V \) is the volume in liters.

2. **Calculate the Molecular Weight of \( O_2 \):**
The molecular weight of \( O_2 \) can be calculated using the atomic mass of oxygen. The atomic mass of oxygen is approximately 16 g/mol. Since \( O_2 \) consists of two oxygen atoms:
\[ \text{Molecular weight of } O_2 = 2 \times 16 \, \text{g/mol} = 32 \, \text{g/mol} \]

3. **Calculate the Number of Moles (N):**
To find the number of moles, we use the formula:
\[ N = \frac{\text{mass}}{\text{molecular weight}} \]
Given that the mass of \( O_2 \) is 96 g:
\[ N = \frac{96 \, \text{g}}{32 \, \text{g/mol}} = 3 \, \text{moles} \]

4. **Calculate the Molar Concentration (C):**
Now that we have the number of moles (N = 3) and the volume (V = 2 L), we can calculate the molar concentration:
\[ C = \frac{N}{V} = \frac{3 \, \text{moles}}{2 \, \text{L}} = 1.5 \, \text{mol/L} \]

5. **Final Answer:**
The molar concentration of 96 g of \( O_2 \) in a 2 L vessel is:
\[ \text{Molar Concentration} = 1.5 \, \text{mol/L} \]