Para toluidine is treated with `HNO_(2)` at ice cold condtions and then boiled with water. The final product obtained is:

Options

A. anthranilic acid
B. p-cresol
C. toluic acid
D. phenol

Answer

To solve the problem of what final product is obtained when para-toluidine is treated with HNO₂ at ice-cold conditions and then boiled with water, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of Para-Toluidine:**
Para-toluidine has a benzene ring with an amino group (–NH₂) and a methyl group (–CH₃) at the para position. The structure can be represented as:
```
NH2
|
C6H4-CH3
```

2. **Reaction with HNO₂ (Diazotization):**
When para-toluidine is treated with nitrous acid (HNO₂) at ice-cold conditions, a diazotization reaction occurs. The amino group (–NH₂) is converted into a diazonium ion (–N₂⁺) at the para position:
```
N2⁺
|
C6H4-CH3
```

3. **Boiling with Water:**
The diazonium salt formed is then treated with boiling water. The water will attack the diazonium group, leading to the loss of nitrogen gas (N₂) and the formation of a hydroxyl group (–OH) at the para position:
```
OH
|
C6H4-CH3
```

4. **Final Product:**
The final product after the reaction is para-cresol (also known as para-methylphenol), which has the following structure:
```
OH
|
C6H4-CH3
```

5. **Conclusion:**
Therefore, the final product obtained from the reaction of para-toluidine with HNO₂ followed by boiling with water is para-cresol.

### Final Answer:
The final product obtained is **para-cresol**.