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If log(6)log(2)[sqrt(4x+2)+2sqrtx]=0then...

If `log_(6)log_(2)[sqrt(4x+2)+2sqrtx]=0thenx=____.`

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To solve the equation \( \log_{6}(\log_{2}(\sqrt{4x+2} + 2\sqrt{x})) = 0 \), we will follow these steps: ### Step 1: Apply the property of logarithms Since \( \log_{6}(y) = 0 \) implies \( y = 6^0 = 1 \), we can rewrite the equation as: \[ \log_{2}(\sqrt{4x + 2} + 2\sqrt{x}) = 1 \] **Hint:** Remember that \( \log_{a}(b) = c \) implies \( b = a^c \). ### Step 2: Solve for the inner logarithm Now, we can convert the logarithmic equation to its exponential form: \[ \sqrt{4x + 2} + 2\sqrt{x} = 2^1 = 2 \] **Hint:** The base of the logarithm tells us what to raise to the power of the result. ### Step 3: Rearrange the equation Next, isolate the square root term: \[ \sqrt{4x + 2} = 2 - 2\sqrt{x} \] **Hint:** To isolate a term, you can move other terms to the opposite side of the equation. ### Step 4: Square both sides Now, square both sides to eliminate the square root: \[ 4x + 2 = (2 - 2\sqrt{x})^2 \] **Hint:** When squaring a binomial, remember to apply the formula \( (a - b)^2 = a^2 - 2ab + b^2 \). ### Step 5: Expand the right side Expanding the right side gives: \[ 4x + 2 = 4 - 8\sqrt{x} + 4x \] **Hint:** Carefully distribute each term when expanding. ### Step 6: Simplify the equation Now, simplify the equation by subtracting \( 4x \) from both sides: \[ 2 = 4 - 8\sqrt{x} \] **Hint:** Combine like terms to simplify the equation. ### Step 7: Isolate the square root Rearranging gives: \[ 8\sqrt{x} = 4 - 2 \] \[ 8\sqrt{x} = 2 \] **Hint:** Always aim to isolate the variable or the term involving the variable. ### Step 8: Solve for \( \sqrt{x} \) Dividing both sides by 8: \[ \sqrt{x} = \frac{2}{8} = \frac{1}{4} \] **Hint:** To isolate the square root, you can divide both sides by the coefficient. ### Step 9: Square both sides again Now, square both sides to find \( x \): \[ x = \left(\frac{1}{4}\right)^2 = \frac{1}{16} \] **Hint:** Squaring a fraction involves squaring both the numerator and the denominator. ### Final Answer Thus, the value of \( x \) is: \[ \boxed{\frac{1}{16}} \]
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