Total number of stereoisomers of compound `CH_(3)-CH=CH-underset(overset(|)(CI))(C)H-CH=CH-CH_(3)` are :

Answer

To determine the total number of stereoisomers for the compound `CH3-CH=CH-(C|Cl)-CH=CH-CH3`, we will follow these steps:

### Step 1: Identify the structure of the compound
The compound can be represented as follows:
```
CH3
|
C
|
CH=CH
|
C
|
CH=CH
|
CH3
```
### Step 2: Count the number of double bonds
In the given compound, there are two double bonds:
1. Between the second and third carbon atoms (C=C)
2. Between the fifth and sixth carbon atoms (C=C)

So, the total number of double bonds (d) = 2.

### Step 3: Identify chiral carbon atoms
A chiral carbon atom is one that has four different groups attached to it. Let's analyze each carbon atom in the compound:

1. **First Carbon (C1)**: Attached to three hydrogen atoms (not chiral).
2. **Second Carbon (C2)**: Attached to one hydrogen, one methyl group (CH3), and one carbon chain (not chiral).
3. **Third Carbon (C3)**: Attached to one hydrogen, one chlorine (Cl), and two identical carbon chains (not chiral).
4. **Fourth Carbon (C4)**: Attached to one hydrogen and two identical carbon chains (not chiral).
5. **Fifth Carbon (C5)**: Attached to one hydrogen and two identical carbon chains (not chiral).
6. **Sixth Carbon (C6)**: Attached to three hydrogen atoms (not chiral).

After analyzing all the carbon atoms, we find that there are **no chiral carbon atoms** in the compound.

### Step 4: Calculate the total number of stereoisomers
The formula to calculate the total number of stereoisomers is:
\[ \text{Total Stereoisomers} = 2^{(n + d)} \]
where \( n \) is the number of chiral centers and \( d \) is the number of double bonds.

Here, \( n = 0 \) (no chiral centers) and \( d = 2 \) (two double bonds).

So, substituting the values:
\[ \text{Total Stereoisomers} = 2^{(0 + 2)} = 2^2 = 4 \]

### Final Answer:
The total number of stereoisomers of the compound `CH3-CH=CH-(C|Cl)-CH=CH-CH3` is **4**.

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