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If cos(theta+phi)=mcos(theta-phi) then t...

If `cos(theta+phi)=mcos(theta-phi)` then `tantheta` is equal to

A

(a) `((1+m)/(1-m)) tan phi`

B

(b) `((1-m)/(1+m)) tan phi`

C

(c) `((1-m)/(1+m)) cot phi`

D

(d) `((1+m)/(1-m)) cot phi`

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A
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