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The sum of the first three terms of the ...

The sum of the first three terms of the `G.P.` in which the difference between the second and the first term is `6` and the difference between the fourth and the third term is` 54`, is

A

39

B

-10.5

C

27

D

-27

Text Solution

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The correct Answer is:
To solve the problem, we need to find the sum of the first three terms of a geometric progression (G.P.) given two conditions about the differences between certain terms. Let's denote the first term of the G.P. as \( a \) and the common ratio as \( r \). The first three terms of the G.P. can be expressed as \( a \), \( ar \), and \( ar^2 \). ### Step 1: Set up the equations based on the given conditions. 1. The difference between the second and first terms is given as \( 6 \): \[ ar - a = 6 \] Factoring out \( a \), we get: \[ a(r - 1) = 6 \quad \text{(Equation 1)} \] 2. The difference between the fourth and third terms is given as \( 54 \): \[ ar^3 - ar^2 = 54 \] Factoring out \( ar^2 \), we get: \[ ar^2(r - 1) = 54 \quad \text{(Equation 2)} \] ### Step 2: Solve the equations. From Equation 1, we can express \( a \): \[ a = \frac{6}{r - 1} \] Now, substitute this expression for \( a \) into Equation 2: \[ \frac{6}{r - 1} \cdot r^2(r - 1) = 54 \] This simplifies to: \[ 6r^2 = 54 \] Dividing both sides by 6: \[ r^2 = 9 \] Taking the square root gives us: \[ r = 3 \quad \text{or} \quad r = -3 \] ### Step 3: Find the corresponding values of \( a \). 1. If \( r = 3 \): \[ a = \frac{6}{3 - 1} = \frac{6}{2} = 3 \] The first three terms are: \[ a = 3, \quad ar = 3 \cdot 3 = 9, \quad ar^2 = 3 \cdot 3^2 = 27 \] 2. If \( r = -3 \): \[ a = \frac{6}{-3 - 1} = \frac{6}{-4} = -\frac{3}{2} \] The first three terms are: \[ a = -\frac{3}{2}, \quad ar = -\frac{3}{2} \cdot (-3) = \frac{9}{2}, \quad ar^2 = -\frac{3}{2} \cdot 9 = -\frac{27}{2} \] ### Step 4: Calculate the sums of the first three terms. 1. For \( r = 3 \): \[ \text{Sum} = 3 + 9 + 27 = 39 \] 2. For \( r = -3 \): \[ \text{Sum} = -\frac{3}{2} + \frac{9}{2} - \frac{27}{2} = -\frac{3}{2} + \frac{9 - 27}{2} = -\frac{3}{2} - \frac{18}{2} = -\frac{21}{2} = -10.5 \] ### Final Answer: The sums of the first three terms of the G.P. are \( 39 \) and \( -10.5 \). ---
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