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If a,b,c,d,e are five positive numbers, ...

If a,b,c,d,e are five positive numbers, then

A

`(a/b+b/c) (c/d+d/e) ge 4 sqrt(a/e)`

B

`b/a+c/b+d/c+e/d+a/ege5`

C

`a/b+b/c+c/d+d/e+e/a lt 5`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given options based on the properties of positive numbers and apply the Arithmetic Mean-Geometric Mean (AM-GM) inequality. ### Step-by-Step Solution: 1. **Understanding the Problem**: We have five positive numbers \( a, b, c, d, e \). We need to analyze four options involving these numbers and determine which of them is true. 2. **Option A**: \[ \frac{a}{b} + \frac{b}{c} + \frac{c}{d} + \frac{d}{e} \geq 4 \sqrt{\frac{a}{e}} \] - We can apply the AM-GM inequality to the first two terms: \[ \frac{a}{b} + \frac{b}{c} \geq 2\sqrt{\frac{a}{c}} \] - For the next two terms: \[ \frac{c}{d} + \frac{d}{e} \geq 2\sqrt{\frac{c}{e}} \] - Combining these results: \[ \frac{a}{b} + \frac{b}{c} + \frac{c}{d} + \frac{d}{e} \geq 2\sqrt{\frac{a}{c}} + 2\sqrt{\frac{c}{e}} \] - Now, applying AM-GM again to the two square roots: \[ 2\sqrt{\frac{a}{c}} + 2\sqrt{\frac{c}{e}} \geq 4\sqrt[4]{\frac{a}{e}} \] - Therefore, Option A is true. 3. **Option B**: \[ \frac{b}{a} + \frac{c}{b} + \frac{d}{c} + \frac{e}{d} + \frac{a}{e} \geq 5 \] - Again, applying AM-GM: \[ \frac{b}{a} + \frac{c}{b} + \frac{d}{c} + \frac{e}{d} + \frac{a}{e} \geq 5\sqrt[5]{\frac{b}{a} \cdot \frac{c}{b} \cdot \frac{d}{c} \cdot \frac{e}{d} \cdot \frac{a}{e}} = 5 \] - Thus, Option B is also true. 4. **Option C**: \[ \frac{a}{b} + \frac{b}{c} + \frac{c}{d} + \frac{d}{e} + \frac{e}{a} < 5 \] - We already established that the minimum value of the left-hand side is 5 (from the application of AM-GM). Therefore, Option C is false. 5. **Conclusion**: - Options A and B are true, while Option C is false.
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