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Consider the equation: 2^(|x+1|)-2^x=|2^...

Consider the equation: `2^(|x+1|)-2^x=|2^x-1|+1` Number of integers less than 15 satisfying the equation are

A

14

B

15

C

16

D

17

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The correct Answer is:
To solve the equation \(2^{|x+1|} - 2^x = |2^x - 1| + 1\), we will analyze it by considering different cases based on the value of \(x\). ### Step 1: Identify critical points The critical points occur when the expressions inside the absolute values change. Here, we have: 1. \(x + 1 = 0 \Rightarrow x = -1\) 2. \(2^x - 1 = 0 \Rightarrow 2^x = 1 \Rightarrow x = 0\) Thus, we will consider three cases based on these critical points: - Case 1: \(x < -1\) - Case 2: \(-1 \leq x < 0\) - Case 3: \(x \geq 0\) ### Step 2: Case 1: \(x < -1\) In this case: - \(|x + 1| = -(x + 1) = -x - 1\) - \(|2^x - 1| = 1 - 2^x\) Substituting these into the equation gives: \[ 2^{-x-1} - 2^x = (1 - 2^x) + 1 \] This simplifies to: \[ 2^{-x-1} - 2^x = 2 - 2^x \] Rearranging terms: \[ 2^{-x-1} = 2 \] This leads to: \[ -x - 1 = 1 \Rightarrow -x = 2 \Rightarrow x = -2 \] ### Step 3: Case 2: \(-1 \leq x < 0\) In this case: - \(|x + 1| = x + 1\) - \(|2^x - 1| = 1 - 2^x\) Substituting these into the equation gives: \[ 2^{x+1} - 2^x = (1 - 2^x) + 1 \] This simplifies to: \[ 2^{x+1} - 2^x = 2 - 2^x \] Rearranging terms: \[ 2^{x+1} = 2 \] This leads to: \[ x + 1 = 1 \Rightarrow x = 0 \] However, \(x = 0\) is not included in this case, so there are no solutions from this case. ### Step 4: Case 3: \(x \geq 0\) In this case: - \(|x + 1| = x + 1\) - \(|2^x - 1| = 2^x - 1\) Substituting these into the equation gives: \[ 2^{x+1} - 2^x = (2^x - 1) + 1 \] This simplifies to: \[ 2^{x+1} - 2^x = 2^x \] Rearranging terms: \[ 2^{x+1} = 2 \cdot 2^x \] This is always true for \(x \geq 0\). Thus, all values of \(x \geq 0\) satisfy the equation. ### Step 5: Count the integer solutions Now we need to count the integer solutions less than 15: - From Case 1, we have \(x = -2\). - From Case 3, all integers \(x = 0, 1, 2, \ldots, 14\) are solutions. Counting these: - From Case 1: 1 solution (\(-2\)) - From Case 3: 15 solutions (0 through 14) ### Total number of integer solutions Total = \(1 + 15 = 16\). Thus, the number of integers less than 15 satisfying the equation is **16**.
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