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For the equation x + y + z +omega= 19, t...

For the equation `x + y + z +omega= 19,` the number of positive integral solutions is equal to-

A

the number of ways in which 15 identical things can be distributed among 4 persons.

B

the number of ways in which 19 identical things can be distributed among 4 persons.

C

coefficient of `x^(19)` in `(x^(0) + x^(1) + x^(2) + "…….." +x^(19))^(4)`

D

coefficient of `x^(19)` in `(x + x^(1) + x^(2) + "…….." +x^(19))^(4)`

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The correct Answer is:
To find the number of positive integral solutions for the equation \( x + y + z + \omega = 19 \), we can use the "stars and bars" theorem from combinatorics. ### Step-by-Step Solution: 1. **Understanding the Problem**: We need to find the number of positive integral solutions to the equation \( x + y + z + \omega = 19 \). This means \( x, y, z, \) and \( \omega \) must all be positive integers. 2. **Transforming the Variables**: Since \( x, y, z, \) and \( \omega \) must be positive integers, we can redefine them to simplify our calculations. Let: \[ x' = x - 1, \quad y' = y - 1, \quad z' = z - 1, \quad \omega' = \omega - 1 \] where \( x', y', z', \omega' \) are non-negative integers (i.e., they can be zero). This transformation gives us: \[ (x' + 1) + (y' + 1) + (z' + 1) + (\omega' + 1) = 19 \] Simplifying this, we get: \[ x' + y' + z' + \omega' = 15 \] 3. **Applying Stars and Bars**: Now, we need to find the number of non-negative integral solutions to the equation \( x' + y' + z' + \omega' = 15 \). According to the stars and bars theorem, the number of ways to distribute \( n \) identical items (stars) into \( k \) distinct groups (bins) is given by: \[ \binom{n + k - 1}{k - 1} \] In our case, \( n = 15 \) (the total we want to achieve) and \( k = 4 \) (the number of variables). 4. **Calculating the Combinations**: Thus, we need to calculate: \[ \binom{15 + 4 - 1}{4 - 1} = \binom{18}{3} \] 5. **Calculating \( \binom{18}{3} \)**: Now we compute \( \binom{18}{3} \): \[ \binom{18}{3} = \frac{18 \times 17 \times 16}{3 \times 2 \times 1} = \frac{4896}{6} = 816 \] ### Final Answer: The number of positive integral solutions to the equation \( x + y + z + \omega = 19 \) is **816**.
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