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Find number of othe ways in which word 'KOLAVARI' can be arranged, if all vowels are separate from each other ?

A

289

B

2880

C

1439

D

1440

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The correct Answer is:
To find the number of ways to arrange the word "KOLAVARI" such that all vowels are separated from each other, we can follow these steps: ### Step 1: Identify the vowels and consonants The word "KOLAVARI" consists of the following letters: - Vowels: O, A, A, I (4 vowels) - Consonants: K, L, V, R (4 consonants) ### Step 2: Arrange the consonants First, we will arrange the consonants. The consonants are K, L, V, R. The number of ways to arrange these 4 consonants is given by: \[ 4! = 24 \] ### Step 3: Create spaces for the vowels Once the consonants are arranged, we need to create spaces for the vowels. Arranging the 4 consonants creates 5 potential spaces for the vowels (before the first consonant, between the consonants, and after the last consonant). For example, if we arrange the consonants as K L V R, the spaces would look like this: \[ \_ K \_ L \_ V \_ R \_ \] ### Step 4: Choose spaces for the vowels We need to select 4 out of these 5 spaces to place the vowels. The number of ways to choose 4 spaces from 5 is given by: \[ \binom{5}{4} = 5 \] ### Step 5: Arrange the vowels Now, we need to arrange the vowels O, A, A, I. Since the letter A is repeated, the number of distinct arrangements of these vowels is given by: \[ \frac{4!}{2!} = \frac{24}{2} = 12 \] ### Step 6: Calculate the total arrangements Now, we can calculate the total number of arrangements by multiplying the number of arrangements of consonants, the number of ways to choose spaces, and the arrangements of vowels: \[ \text{Total arrangements} = (4!) \times \binom{5}{4} \times \frac{4!}{2!} \] Substituting the values we calculated: \[ \text{Total arrangements} = 24 \times 5 \times 12 = 1440 \] ### Final Answer Thus, the total number of ways to arrange the word "KOLAVARI" such that all vowels are separated from each other is **1440**.
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