Home
Class 12
MATHS
Number of ways in which four different t...

Number of ways in which four different toys and five indistinguishable marbles can be distributed between 3 boys, if each boy receives at least one toy and at least one marble

A

42

B

100

C

150

D

216

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of distributing four different toys and five indistinguishable marbles among three boys such that each boy receives at least one toy and at least one marble, we can break down the solution into two parts: distributing the marbles and distributing the toys. ### Step 1: Distributing the Marbles 1. **Initial Distribution**: Since each boy must receive at least one marble, we start by giving one marble to each of the three boys. This uses up 3 marbles, leaving us with \(5 - 3 = 2\) marbles. 2. **Distributing Remaining Marbles**: Now we need to distribute the remaining 2 indistinguishable marbles among the 3 boys. We can use the "stars and bars" theorem for this distribution. The formula for distributing \(n\) indistinguishable items into \(r\) distinguishable boxes is given by: \[ \text{Number of ways} = \binom{n + r - 1}{r - 1} \] Here, \(n = 2\) (remaining marbles) and \(r = 3\) (boys). Thus, we calculate: \[ \text{Number of ways} = \binom{2 + 3 - 1}{3 - 1} = \binom{4}{2} = 6 \] ### Step 2: Distributing the Toys 1. **Initial Distribution**: Each boy must receive at least one toy. We can give one toy to each of the three boys. This uses up 3 toys, leaving us with \(4 - 3 = 1\) toy. 2. **Distributing Remaining Toy**: Now we need to distribute the remaining 1 toy among the 3 boys. Since the toys are different, we can choose any of the 3 boys to receive the extra toy. Thus, there are 3 ways to distribute this toy. ### Step 3: Total Combinations To find the total number of ways to distribute both the marbles and the toys, we multiply the number of ways to distribute the marbles by the number of ways to distribute the toys: \[ \text{Total ways} = (\text{Ways to distribute marbles}) \times (\text{Ways to distribute toys}) = 6 \times 3 = 18 \] ### Final Answer The total number of ways to distribute the four different toys and five indistinguishable marbles among three boys, ensuring each boy receives at least one toy and one marble, is **18**. ---
Promotional Banner

Topper's Solved these Questions

  • DEFINITE INTEGRATION & ITS APPLICATION

    RESONANCE ENGLISH|Exercise High Level Problem|26 Videos
  • EQUATIONS

    RESONANCE ENGLISH|Exercise EXERCISE-2 (PART-II: PREVIOUSLY ASKED QUESTION OF RMO) |5 Videos

Similar Questions

Explore conceptually related problems

The number of ways in which 5 distinct toys can be distributed among 8 children is

The number of ways in which 20 identical coins be distributed in 4 persons if each person receive at least 2 coins and atmost 5 coins, are

Six apples and six mangoes are to be distributed among ten boys so that each boy receives at least one fruit. Find the number ways in which the fruits can be distributed.

Find the number of ways in which 8 distinct toys can be distributed among 5 children.

Find the number of ways in which 8 distinct toys can be distributed among 5 children.

Number of ways in which 5 different toys can be distributed in 5 children if exactly one child does not get any toy is greater than

Statement 1: number of ways in which 10 identical toys can be distributed among three students if each receives at least two toys is .^6C_2 . Statement 2: Number of positive integral solutions of x+y+z+w=7i s^6C_3dot

The total number of ways in which 5 balls of different colours can be distributed among 3 persons so that each person gets at least one ball is

The number of ways in which thirty five apples can be distributed among 3 boys so that each can have any number of apples, is :

Find the number of ways in which 8 non-identical apples can be distributed among 3 boys such that every boy should get at least 1 apple and at most 4 apples.

RESONANCE ENGLISH-DPP-QUESTION
  1. The number of integral solutions of the inequation x+y+z le 100, (x ge...

    Text Solution

    |

  2. Find number of othe ways in which word 'KOLAVARI' can be arranged, if ...

    Text Solution

    |

  3. Number of ways in which four different toys and five indistinguishable...

    Text Solution

    |

  4. We are required to form different words with the help of the letters o...

    Text Solution

    |

  5. If the lines a x+2y+1=0,b x+3y+1=0a n dc x+4y+1=0 are concurrent, then...

    Text Solution

    |

  6. If the point (1+cos theta, sin theta) lies between the region correspo...

    Text Solution

    |

  7. The line 2x+3y=12 meets the x-axis at A and y-axis at B. The line thro...

    Text Solution

    |

  8. Equation of straight line a x+b y+c=0 , where 3a+4b+c=0 , which is at ...

    Text Solution

    |

  9. If the straight lines joining the origin and the points of intersectio...

    Text Solution

    |

  10. Statement-1 :Perpendicular from origin O to the line joining the point...

    Text Solution

    |

  11. The point (11 ,10) divides the line segment joining the points (5,-2) ...

    Text Solution

    |

  12. The algebraic sum of the perpendicular distances from A(x1, y1), B(x2,...

    Text Solution

    |

  13. In a flower bed there are 23 rose plants in the first row, twenty o...

    Text Solution

    |

  14. A committee of 10 is to be formed from 8 teachers and 12 students of w...

    Text Solution

    |

  15. 5 boys & 4 girls sit in a straight line. Find the number of ways in wh...

    Text Solution

    |

  16. The equations of perpendicular bisectors o the sides AB and AC of a ...

    Text Solution

    |

  17. The equation of perpendicular bisectors of the side AB and AC of a tri...

    Text Solution

    |

  18. Sum of the n terms of the series (3)/(1^(2))+(5)/(1^(2)+2^(2))+(7)/(1^...

    Text Solution

    |

  19. Find equations of acute and obtuse angle bisectors of the angle betwee...

    Text Solution

    |

  20. If 4a^2+c^2=b^2-4a c , then the variable line a x+b y+c=0 always passe...

    Text Solution

    |