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A Particle move from the point (2.0 hat...

A Particle move from the point `(2.0 hati + 4.0 hatj)m`, at t 0 , with an initial velocity `(5.0 hati + 4.0hati)ms^(-1)`. It is acted upon by a constant force which prouduces a constant acceleration `(4.0hati + 4.0 hatj) ms^(-2)`. What is the distance of the particle from the origin at time 2 s?

A

`20sqrt2 m`

B

`15m`

C

`5m`

D

`10 sqrt2m`

Text Solution

Verified by Experts

The correct Answer is:
A
Position at time t,
`vec r_(t) = (2+5t + 1/2 xx 4t ^(2))hti + (4 + 4t + 1/2 xx 4t ^(2))j`
`vecr _(t=2) = 20 hati+ 20 hatj" "therefore` Distance from origin, is `20sqrt2m.`
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