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A galvanometer having a resistance of ...

A galvanometer having a resistance of `20 Omega` and 30 divisible on both sides has figure of merit 0.005 ampere/division. The resistance that should be connected in series such that it can be used as a voltmeter upto 15 volt, is :

A

`120Omega`

B

`100 Omega`

C

`125 Omega`

D

`80 Omega `

Text Solution

Verified by Experts

The correct Answer is:
D
Since `V = I _(g) . R _(g) [1+ (R_(v))/(R _(g))]`
`15=0.005xx30xx20 [1+ (R _(v))/(20)] " "implies (R_(v))/(20) = (15)/(0.15 xx20) -1 implies R_(v) =80 Omega`
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