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In the circuit shown, the potential dif...

In the circuit shown, the potential difference between A and B is .

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The correct Answer is:
2
Equvalent circuit is
`r _(eq) = (1)/((1)/(1)+ (1)/(1) + (1)/(1))=1/3 Omega `
Now `(E_(eq))/(r _(eq))=(E_(1))/(r_(1))+ (E_(2))/(r_(2))+ (E_(3))/(r _(3))implies 3E_(eq) =1+2+3implies E_(eq) =2V`
Now `V_(A)-V_(B) =E_(eq) =2 ` Volts.
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