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In a process, temperature and volume of ...

In a process, temperature and volume of one mole of an ideal monoatomic gas are varied according to the relation VT= K, where K is a constant. In this process the temperataure of the gas is increased by `DeltaT`. The amount of heat absorbed by gas is (R is gas constant).

Text Solution

Verified by Experts

The correct Answer is:
`(R Delta T)/(2)`
`VT=K implies PV ^(2) =K' (K'=nRK)`
Clearly it is a polytropic process with `n =2.`
`Delta theta = Delta U + omega or Delta theta = C_(V) Delta T + (R Detla )/(1-n) or C _(V) = (R Delta T)/(2).`
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