Home
Class 12
PHYSICS
The magnitude of torque on a particle of...

The magnitude of torque on a particle of mass 1 kg is 2.5 Nm about the origin.If the force acting it is 1 N, and the distance of the particle from the origin is 5 m, the angle between the force and the position vector is (in radians):

Text Solution

Verified by Experts

The correct Answer is:
6
`tau=FR sin theta`
`sin theta = (2.5)/(1xx5)" "therefore theta =30^(@).`
Promotional Banner

Topper's Solved these Questions

  • JEE MAIN REVISION TEST 5 (2020)

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos

  • JEE MAIN REVISION TEST 11 (2020)

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION - 2)|5 Videos

  • JEE MAIN REVISION TEST 8 (2020)

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos

Similar Questions

Explore conceptually related problems

The gravitational field in a region is given by vecE=(5Nkg^-1)veci+(12Nkg^-1)vecj. . a. find the magnitude of the gravitational force acting on a particle of mass 2 kg placed at the origin b. Find the potential at the points (12m,0) and (0,5m) if the potential at the origin is taken to be zero. c. Find the change in gravitational potential energy if a particle of mass 2 kg is taken from the origin to the point (12m,5m). d. Find the change in potential energy if the particle is taken from (12m,0) to (0,5m) .

Find the torque about the origin when a force of 3 hatj N acts on a particle whose position vector is 2 hatk m

A particle mass 1 kg is moving along a straight line y=x+4 . Both x and y are in metres. Velocity of the particle is 2m//s . Find the magnitude of angular momentum of the particle about origin.

The moment of a force of 50 N about a point is 5 Nm. Find the perpendicular distance of force from that point.

Find the torque of a force (7 hati + 3hatj - 5hatk) about the origin. The force acts on a particle whose position vector is (hati - hatj + hatk) .

A force Fhatk acts on O, the origin of the coordinate system. The torque of this force about the point is: (1,-1) is

A time dependent force F=6t acts on a particle of mass 1kg . If the particle starts from rest, the work done by the force during the first 1 sec. will be

A single force acts on a particle situated on the negative x-axis. The torque about the origin is in the positive z-direction. The force is

A particle of mass m moves on positive x-axis under the influence of force acting towards the origin given by -kx^2 hat i. If the particle starts from rest at x=a, the speed it will attain when it crosses the origin is

Consider a system of two particles having masses m_(1) and m_(2) . If the particle of mass m_(1) is pushed towards the centre of mass of particles through a distance d , by what distance would the particle of mass m_(2) move so as to keep the mass centre of particles at the original position?