Home
Class 12
PHYSICS
If He^(+) ion is in its first excited st...

If `He^(+)` ion is in its first excited state then its ionization energy is

A

6.04 eV

B

48.36 eV

C

54.40 eV

D

13.60 eV

Text Solution

Verified by Experts

The correct Answer is:
D

`E_(n) = - 13.6 (z^(2))/(n^(2)), n = 2, z = 2`
`E = - 13.6 xx (2^(2))/(2^(2)) = - 13.6 eV`
Promotional Banner

Topper's Solved these Questions

  • JEE MAIN REVISION TEST 11 (2020)

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION - 2)|5 Videos
  • JEE MAIN REVISION TEST -17 (2020)

    VMC MODULES ENGLISH|Exercise PHYSICS|25 Videos
  • JEE MAIN REVISION TEST 5 (2020)

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos

Similar Questions

Explore conceptually related problems

A He^(+) ion is in its first excited state. Its ionization energy is

The groud state energy of hydrogen atom is -13.6 eV . When its electron is in first excited state, its exciation energy is

Statement-1 : The excitation energy of He^(+) in its first excited state is 4 times the excitation energy of H in its first excited state. Statement-2 : The whose energies are defined by the expansion E= -(E_(0)Z^(2))/(n^(2)) are stable, where Z and n are atomic number of the atom and principal quantum number of the orbit, respectively.

(a) Find the maximum wavelength lambda_90) of light which can ionize a hydrogen atom in its ground (b) light of wavelength lambda_(0) is inclined on ahydrogen atom which is in its first excited state find the kinrtic energy of the electron coming out

When a hydrogen atom is excited from ground state to first excited state, then a)its kinetic energy increased by 20 eV b)its kinetic energy decreased by 10.2 eV c)its potential energy increased by 20.4 eV d)its angular momentum increased by 1.05×10^-34Js

What is the energy of a hydrogen atom in the first excited state if the potential energy is taken to be zero in the ground state?

What is the energy of a hydrogen atom in the first excited state if the potential energy is taken to be zero in the ground state?

When the light of wavelength 400 nm is incident on a metal surface of work function 2.3 eV , photoelectrons are emitted. A fasted photoelectron combines with a He^(2+) ion to form He^(+) ion in its third excited state and a photon is emitted in this process. Then the energy of the photon emitted during combination is

The excitation energy of a hydrogen -like ion in its first excited state is 40.8 eV Find the energy needed to remain the electron from the ion

The excitation energy of a hydrogen-like ion in its first excited state is 40.8 eV Find the energy needed to remove the electron from the ion