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For position of real object at x(1) and ...

For position of real object at `x_(1)` and `x_(2)` (x_(2)gtx_(1)` magnification is equal to 2. find out `(x_(1))/(x_(2))` if focal length of converging lens `f=20cm`

A

`4 : 3`

B

`5 : 3`

C

`3 : 1`

D

`2 : 1`

Text Solution

Verified by Experts

The correct Answer is:
C
Magnification is 2
If imange is real `x_(1) = (3f)/(2)`
If image is virtual, `x_(2) = (F)/(2)`
`(x_(1))/(x_(2)) 3 : 1`
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