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In a Young’s double slit experiment, the...

In a Young’s double slit experiment, the ratio of the slit’s width is 4 : 1. The ratio of the intensity of maxima to minima, close to the central fringe on the screen, will be:

A

`(sqrt3 + 1)^(4) : 16`

B

`25 :9`

C

`4 : 1`

D

`9 : 1`

Text Solution

Verified by Experts

The correct Answer is:
D
`I_(1) : I_(2) = 4 : 1`
`(I_("max"))/(I_("min")) = ((sqrtI_(1) + sqrtI_(2))^(2))/((sqrt(I_(1)) - sqrt(I_(2)))^(2)) = ((3I)/(I))^(2) = (9)/(1)`
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