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Water from a tap emerges vertically down...

Water from a tap emerges vertically downwards with an initial speed of `1.0m//s`. The cross-section area of tap is `10^(-4)m^(2)`.Assume that the pressure is constant throughout the stream of water and that the flow is steady, the cross-sectional area of steam `0.15 m` below the tap is

A

`5 xx 10^(-4) m^(2)`

B

`1 xx 10^(-5) m^(2)`

C

`2 xx 10^(-5) m^(2)`

D

`5 xx 10^(-5) m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`P_(0) + rho gh + (1)/(2) rho v_(1)^(2) = P_(0) + (1)/(2) rho v_(2)^(2)`
`rArr V_(2)^(2) = V_(1)^(2) + 2gh`
`V_(2) = 2m//s`
`A_(1)V_(1) = A_(2)V_(2)`
`rArr A_(2) = (10^(-4))/(2) = 5 xx 10^(-5) m^(2)`
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