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A spaceship orbits around a planet at a ...

A spaceship orbits around a planet at a height of 20 km from its surface. Assuming that only gravitational field of the planet acts on the spaceshop. What will be the number of complete revolutions made by the spaceship in 24 hours around the planet?
[Given mass of plane `=8xx10^(22)kg`
Radius of planet `=2xx10^(6)m`
Gravitational constant `G=6.67xx10^(-11)Nm^(2)//kg^(2)`]

A

9

B

11

C

13

D

27

Text Solution

Verified by Experts

The correct Answer is:
B
`v_(0) = sqrt((GM)/( R ) rArr omega = (v_(0))/(r ) = sqrt((GM)/(r^(3)) = (2pi n)/(24 xx 60 xx 60) rArr n = 11`
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