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A coil of self inductance 10 mH and resi...

A coil of self inductance 10 mH and resistance 0.1 `Omega` is connected through a switch battery of internal resistance `0.9Omega` after the switch is closed, the time taken for the current to attain `80%` of the saturation value is [taken `ln5=1.6`]

A

`0.016s`

B

`0.324s`

C

`0.002s`

D

`0.103s`

Text Solution

Verified by Experts

The correct Answer is:
A
`i = i_(0) (1 - e^(-Rt//L)) rArr 0.8 i_(0) = i_(0) (1 - e^(-Rt//L))`
`t = (L)/( R) l n5 = (10 xx 10^(-3) xx 1.6)/((0.9 + 0.1)) = 0.016s`
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