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A simple pendulum of length L is placed ...

A simple pendulum of length L is placed between the plates of a parallel plate capacitor having electric field E, as shown in figure. Its bob has mass m and charge q. The time period of the pendulum is given by:

A

`2pi sqrt((L)/(sqrt(g^(2) + ((qE)/(m))^(2))))`

B

`2pi sqrt((L)/(sqrt(g^(2) - ((qE)/(m))^(2))))`

C

`2pi sqrt((L)/((g-(qE)/(m))))`

D

`2pi sqrt((L)/((g + (qE)/(m))))`

Text Solution

Verified by Experts

The correct Answer is:
A
`g_(eff) = sqrt(g^(2) + ((qE)/(m))^(2))`
`T = 2pi sqrt(l)/(g_(eff))`
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