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Two radioactive substances A and B have ...

Two radioactive substances A and B have decay constants `5lambda` and `lambda` respectively. At t=0 , they have the same number of nuclei. The ratio of number of nuclei of A of those of B will be `(1//e)^2` after a time interval

Text Solution

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The correct Answer is:
`0.50`
`N_(A) = N_(0) e^(-5 lamda t)" " N_(B) = N_(0) e^(- lamda t)`
`(N_(A))/(N_(B)) = (1)/(e^(2)) rArr (e^(-5lamda t))/(e^(-lamda t)) = (1)/(e^(2)) rArr 4 lamda t = 2`
`t = (1)/(2 lamda)`
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