A halide with formula `C_(6)H_(13)Br` gave two isomeric alkenes A and B with formula `C_(6)H_(12)`. On reductive ozonolysis of mixture of A and B following compounds were obtained `CH_(3)COCH_(3), CH_(3)CHO, CH_(3)CH_(2)CHO` and `(CH_(3))_(2)CHCHO`. Thehalide is

Options

A. 2 - Bromohexane
B. 3 - Bromo - 2 - methylpentane
C. 2,2 - Dimethyl - 1 - bromobutane
D. 2 - Bromo -2,3 - dimethylbutane

Explanation

To determine the halide with the formula \( C_6H_{13}Br \) that gives two isomeric alkenes \( A \) and \( B \) with the formula \( C_6H_{12} \), we can follow these steps:

### Step 1: Identify the Alkenes
The alkenes formed from the halide must have the formula \( C_6H_{12} \). This indicates that the alkenes are likely to be derived from the elimination of HBr from the halide.

### Step 2: Analyze the Products of Ozonolysis
The ozonolysis of the alkenes yields the following products:
1. \( CH_3COCH_3 \) (acetone)
2. \( CH_3CHO \) (acetaldehyde)
3. \( CH_3CH_2CHO \) (propionaldehyde)
4. \( (CH_3)_2CHCHO \) (isobutyraldehyde)

### Step 3: Determine the Structure of the Alkenes
From the ozonolysis products, we can deduce the structures of the alkenes. The presence of acetone suggests that one of the alkenes has a branched structure, while the aldehydes indicate the presence of terminal double bonds.

### Step 4: Propose Possible Alkenes
Based on the products, we can propose two possible alkenes:
1. **Alkene A**: 2-methylpent-2-ene
2. **Alkene B**: 4-methylpent-2-ene

### Step 5: Identify the Halide
To obtain these alkenes from a halide, we consider the elimination reactions:
- For **2-methylpent-2-ene**, the corresponding halide would be **2-bromo-2-methylpentane**.
- For **4-methylpent-2-ene**, the corresponding halide would be **3-bromo-2-methylpentane**.

### Step 6: Conclusion
The halide that can produce both alkenes is **3-bromo-2-methylpentane**.

### Final Answer
The halide is **3-bromo-2-methylpentane**.

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