`H_(2)O_(2)` on treatment with chlorine gives:

Options

A. `H_(2)`
B. Oxygen
C. Hypochlorous acid
D. `ClO_(2)`

Explanation

To solve the question regarding the reaction of hydrogen peroxide (H₂O₂) with chlorine (Cl₂), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are hydrogen peroxide (H₂O₂) and chlorine (Cl₂).

2. **Understand the Nature of H₂O₂**:
Hydrogen peroxide is known to act as both an oxidizing agent and a reducing agent. This means it can participate in both oxidation and reduction reactions.

3. **Write the Reaction**:
When hydrogen peroxide reacts with chlorine, the products formed are hydrochloric acid (HCl) and oxygen (O₂). The reaction can be represented as:
\[ \text{H}_2\text{O}_2 + \text{Cl}_2 \rightarrow \text{HCl} + \text{O}_2 \]

4. **Balance the Equation**:
To ensure that the number of atoms of each element is the same on both sides of the equation, we need to balance it. The balanced equation is:
\[ \text{H}_2\text{O}_2 + 2\text{Cl}_2 \rightarrow 2\text{HCl} + \text{O}_2 \]
Here, we have 2 chlorine atoms and 2 hydrogen atoms on both sides.

5. **Identify the Products**:
From the balanced equation, we can see that the products of the reaction are hydrochloric acid (HCl) and oxygen (O₂).

6. **Conclusion**:
Therefore, when hydrogen peroxide (H₂O₂) is treated with chlorine (Cl₂), it produces hydrochloric acid (HCl) and oxygen (O₂).

### Final Answer:
When H₂O₂ is treated with Cl₂, it gives HCl and O₂.

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