Home
Class 12
PHYSICS
The ratio of binding energy of a satel...

The ratio of binding energy of a satellite at rest on earth's surface to the binding energy of a satellite of same mass revolving around of the earth at a height h above the earth's surface is (R = radius of the earth).

A

(a)`(2(R + h))/(R )`

B

(b)`(R + h)/(2R)`

C

(c)`(R + h)/(R )`

D

(d)`R/(R + h)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio of the binding energy of a satellite at rest on the Earth's surface to the binding energy of a satellite of the same mass revolving around the Earth at a height \( h \) above the Earth's surface, we can follow these steps: ### Step 1: Understand the Binding Energy Formula The binding energy \( E \) of a satellite is given by the formula: \[ E = -\frac{G M m}{r} \] where: - \( G \) is the gravitational constant, - \( M \) is the mass of the Earth, - \( m \) is the mass of the satellite, - \( r \) is the distance from the center of the Earth to the satellite. ### Step 2: Calculate Binding Energy at Rest on Earth's Surface For a satellite at rest on the Earth's surface, the distance \( r \) is equal to the radius of the Earth \( R \): \[ E_{\text{rest}} = -\frac{G M m}{R} \] ### Step 3: Calculate Binding Energy of Satellite in Orbit For a satellite revolving at a height \( h \) above the Earth's surface, the distance \( r \) from the center of the Earth is \( R + h \): \[ E_{\text{orbit}} = -\frac{G M m}{R + h} \] ### Step 4: Find the Ratio of Binding Energies Now, we need to find the ratio of the binding energy at rest to the binding energy in orbit: \[ \text{Ratio} = \frac{E_{\text{rest}}}{E_{\text{orbit}}} = \frac{-\frac{G M m}{R}}{-\frac{G M m}{R + h}} = \frac{R + h}{R} \] ### Step 5: Simplify the Ratio The ratio can be simplified to: \[ \text{Ratio} = \frac{R + h}{R} = 1 + \frac{h}{R} \] ### Conclusion Thus, the ratio of the binding energy of a satellite at rest on the Earth's surface to that of a satellite revolving at a height \( h \) above the Earth's surface is: \[ \text{Ratio} = 1 + \frac{h}{R} \]

To find the ratio of the binding energy of a satellite at rest on the Earth's surface to the binding energy of a satellite of the same mass revolving around the Earth at a height \( h \) above the Earth's surface, we can follow these steps: ### Step 1: Understand the Binding Energy Formula The binding energy \( E \) of a satellite is given by the formula: \[ E = -\frac{G M m}{r} \] where: ...
Promotional Banner

Topper's Solved these Questions

  • JEE MAIN REVISION TEST - 18

    VMC MODULES ENGLISH|Exercise PHYSICS - SECTION 2|5 Videos
  • JEE MAIN REVISION TEST - 13

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos
  • JEE MAIN REVISION TEST - 19

    VMC MODULES ENGLISH|Exercise PHYSICS|25 Videos

Similar Questions

Explore conceptually related problems

What will be velocity of a satellite revolving around the earth at a height h above surface of earth if radius of earth is R :-

For a satellite orbiting very close to earth's surface, total energy is

Find the period of revolution of a satellite revolving the earth at a height of 200km above earth's surface ? Radius of earth = 6400 km

The potential energy of a satellite of mass m revolving at height R above the surface of the earth where R= radius of earth is

If the kinetic energy of a satellite orbiting around the earth is doubled then

Find work done in shifting a body of mass m from a height h above the earth's surface to a height 2h above the earth's surface..

Binding energy of moon and earth is :-

At a height H from the surface of earth, the total energy of a satellite is equal to the potential energy of a body of equal mass at a height 3R from the surface of the earth (R = radius of the earth). The value of H is

If height of a satellite from the surface of earth is increased , then its

At what height from the surface of the earth, the total energy of satellite is equal to its potential energy at a height 2R from the surface of the earth ( R =radius of earth)