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The number of numbers lying between 100 ...

The number of numbers lying between 100 and 500 that are divisible by 7 but not 21 is

A

57

B

19

C

38

D

76

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The correct Answer is:
To solve the problem of finding the number of numbers lying between 100 and 500 that are divisible by 7 but not by 21, we can follow these steps: ### Step 1: Identify the Range We need to find numbers between 100 and 500. ### Step 2: Find the First and Last Terms Divisible by 7 - The smallest number greater than 100 that is divisible by 7 is 105 (since 105 = 7 × 15). - The largest number less than 500 that is divisible by 7 is 497 (since 497 = 7 × 71). ### Step 3: Determine the Sequence of Numbers Divisible by 7 The sequence of numbers divisible by 7 between 100 and 500 is: 105, 112, 119, ..., 497. This is an arithmetic progression (AP) where: - First term (a) = 105 - Common difference (d) = 7 - Last term (L) = 497 ### Step 4: Calculate the Number of Terms (n) in the AP Using the formula for the nth term of an AP: \[ L = a + (n - 1) \cdot d \] Substituting the known values: \[ 497 = 105 + (n - 1) \cdot 7 \] Rearranging gives: \[ (n - 1) \cdot 7 = 497 - 105 \] \[ (n - 1) \cdot 7 = 392 \] \[ n - 1 = \frac{392}{7} \] \[ n - 1 = 56 \] \[ n = 57 \] So, there are 57 numbers between 100 and 500 that are divisible by 7. ### Step 5: Find the Numbers Divisible by 21 Next, we need to find the numbers that are divisible by 21 in the same range. - The smallest number greater than 100 that is divisible by 21 is 105 (since 105 = 21 × 5). - The largest number less than 500 that is divisible by 21 is 483 (since 483 = 21 × 23). The sequence of numbers divisible by 21 is: 105, 126, 147, ..., 483. This is also an AP where: - First term (a) = 105 - Common difference (d) = 21 - Last term (L) = 483 ### Step 6: Calculate the Number of Terms (m) in this AP Using the same formula for the nth term: \[ L = a + (m - 1) \cdot d \] Substituting the known values: \[ 483 = 105 + (m - 1) \cdot 21 \] Rearranging gives: \[ (m - 1) \cdot 21 = 483 - 105 \] \[ (m - 1) \cdot 21 = 378 \] \[ m - 1 = \frac{378}{21} \] \[ m - 1 = 18 \] \[ m = 19 \] So, there are 19 numbers between 100 and 500 that are divisible by 21. ### Step 7: Calculate the Numbers Divisible by 7 but Not by 21 To find the numbers that are divisible by 7 but not by 21, we subtract the count of numbers divisible by 21 from those divisible by 7: \[ \text{Numbers divisible by 7 but not by 21} = n - m \] \[ = 57 - 19 \] \[ = 38 \] ### Final Answer Thus, the number of numbers lying between 100 and 500 that are divisible by 7 but not by 21 is **38**. ---
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