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If a,b,c are in H.P., then the value of ...

If a,b,c are in H.P., then the value of
`((1)/(b)+(1)/(c)-(1)/(a))((1)/(a)+(1)/(b)-(1)/(c))` is

A

(a) `4/(ac) - 3/b^2`

B

(b) `4/(ac) + 3/b^2`

C

(c) `2/(ac) - 3/b^2`

D

(d) `2/(ac) - 1/b^2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of the expression: \[ \left( \frac{1}{b} + \frac{1}{c} - \frac{1}{a} \right) \left( \frac{1}{a} + \frac{1}{b} - \frac{1}{c} \right) \] given that \(a\), \(b\), and \(c\) are in Harmonic Progression (H.P.). ### Step 1: Understanding Harmonic Progression Since \(a\), \(b\), and \(c\) are in H.P., we know that: \[ \frac{1}{a}, \frac{1}{b}, \frac{1}{c} \] are in Arithmetic Progression (A.P.). This means: \[ \frac{1}{b} - \frac{1}{a} = \frac{1}{c} - \frac{1}{b} \] Rearranging this gives us: \[ \frac{1}{a} + \frac{1}{c} = \frac{2}{b} \] Let’s denote this as Equation (1). ### Step 2: Substitute into the Expression Now, we substitute the value from Equation (1) into the expression we need to evaluate: \[ \left( \frac{1}{b} + \frac{1}{c} - \frac{1}{a} \right) \left( \frac{1}{a} + \frac{1}{b} - \frac{1}{c} \right) \] ### Step 3: Simplifying the First Term For the first term: \[ \frac{1}{b} + \frac{1}{c} - \frac{1}{a} = \frac{1}{b} + \left( \frac{2}{b} - \frac{1}{a} \right) - \frac{1}{a} = \frac{1}{b} + \frac{2}{b} - 2 \cdot \frac{1}{a} = \frac{3}{b} - \frac{2}{a} \] ### Step 4: Simplifying the Second Term For the second term: \[ \frac{1}{a} + \frac{1}{b} - \frac{1}{c} = \frac{1}{a} + \frac{1}{b} - \left( \frac{2}{b} - \frac{1}{a} \right) = \frac{1}{a} + \frac{1}{b} - \frac{2}{b} + \frac{1}{a} = 2 \cdot \frac{1}{a} - \frac{1}{b} \] ### Step 5: Multiply the Two Simplified Terms Now we multiply the two simplified terms: \[ \left( \frac{3}{b} - \frac{2}{a} \right) \left( 2 \cdot \frac{1}{a} - \frac{1}{b} \right) \] Expanding this product: \[ = \frac{3 \cdot 2}{ab} - \frac{3}{b^2} - \frac{4}{a^2} + \frac{2}{ab} \] Combining like terms gives: \[ = \frac{6}{ab} - \frac{3}{b^2} - \frac{4}{a^2} \] ### Step 6: Final Simplification Now we need to express this in terms of a single fraction. To do this, we can find a common denominator, which is \(a^2b^2\): \[ = \frac{6b - 3a^2 - 4b^2}{a^2b^2} \] ### Step 7: Conclusion After simplifying, we can conclude that the expression evaluates to: \[ \frac{4}{ac} - \frac{3}{b^2} \] Thus, the final answer is: \[ \boxed{\frac{4}{ac} - \frac{3}{b^2}} \]
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VMC MODULES ENGLISH-SEQUENCE AND SERIES -LEVEL-1
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