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The sum of the first n terms of the seri...

The sum of the first n terms of the series `1^2+2xx2^2+3^2+2xx 4^2+5^2+2xx6^2…..is (n(n+1)^2)/(2)` when n is even .Then find the sum when n is odd.

A

`(n^2 (n+1))/2`

B

`(n(n+1)^2)/2`

C

`[(n^2 (n+1))/2]^(-2)`

D

`(n(n+1))/2`

Text Solution

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The correct Answer is:
A
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