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The least value of 2log100 a-loga 0.0001...

The least value of 2`log_100 a-log_a 0.0001 , a >1`

A

2

B

3

C

4

D

6

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The correct Answer is:
To find the least value of the expression \(2 \log_{100} a - \log_a 0.0001\) for \(a > 1\), we will proceed step by step. ### Step 1: Rewrite the logarithmic expression First, we rewrite the expression using the properties of logarithms. We know that: \[ \log_a 0.0001 = \log_a (10^{-4}) = -4 \log_a 10 \] Thus, we can rewrite the original expression as: \[ 2 \log_{100} a - (-4 \log_a 10) = 2 \log_{100} a + 4 \log_a 10 \] ### Step 2: Change the base of the logarithm Next, we can change the base of the logarithm from 100 to 10. We use the change of base formula: \[ \log_{100} a = \frac{\log_{10} a}{\log_{10} 100} = \frac{\log_{10} a}{2} \] So, we can substitute this back into our expression: \[ 2 \left(\frac{\log_{10} a}{2}\right) + 4 \log_a 10 = \log_{10} a + 4 \log_a 10 \] ### Step 3: Rewrite \(\log_a 10\) Using the change of base formula again, we can express \(\log_a 10\) as: \[ \log_a 10 = \frac{1}{\log_{10} a} \] Substituting this into the expression gives: \[ \log_{10} a + 4 \left(\frac{1}{\log_{10} a}\right) \] ### Step 4: Let \(x = \log_{10} a\) Let \(x = \log_{10} a\). Since \(a > 1\), we have \(x > 0\). The expression now becomes: \[ f(x) = x + \frac{4}{x} \] ### Step 5: Find the minimum value of \(f(x)\) To find the minimum value of \(f(x)\), we can take the derivative and set it to zero: \[ f'(x) = 1 - \frac{4}{x^2} \] Setting the derivative equal to zero: \[ 1 - \frac{4}{x^2} = 0 \implies \frac{4}{x^2} = 1 \implies x^2 = 4 \implies x = 2 \quad (\text{since } x > 0) \] ### Step 6: Evaluate \(f(x)\) at \(x = 2\) Now, we evaluate \(f(x)\) at \(x = 2\): \[ f(2) = 2 + \frac{4}{2} = 2 + 2 = 4 \] ### Step 7: Verify that this is a minimum To confirm that this is indeed a minimum, we can check the second derivative: \[ f''(x) = \frac{8}{x^3} \] Since \(f''(x) > 0\) for \(x > 0\), \(f(x)\) is concave up, confirming that \(x = 2\) is a minimum. ### Conclusion Thus, the least value of the expression \(2 \log_{100} a - \log_a 0.0001\) for \(a > 1\) is: \[ \boxed{4} \]
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