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The sum of the product taken two at a ti...

The sum of the product taken two at a time of the numbers `1,2,2^2,2^3,.....2^(n-2),2^(n-1)` is (a) `1/3 . 2^(2n) +2/3` (b) `1/3. 2^(2n) -2^n + 1/3` (c) `1/3. 3^(2n) -1/3` (d) none of these

A

`1/3 . 2^(2n) +2/3`

B

`1/3. 2^(2n) -2^n + 1/3`

C

`1/3. 3^(2n) -1/3`

D

`1/3 . 2^(2n) -2^n + 2/3`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the sum of the products taken two at a time from the series: \(1, 2, 2^2, 2^3, \ldots, 2^{n-2}, 2^{n-1}\). ### Step-by-Step Solution: 1. **Identify the series**: The series consists of the terms \(2^0, 2^1, 2^2, \ldots, 2^{n-1}\). This can be rewritten as: \[ a_1 = 1, \quad a_2 = 2, \quad a_3 = 2^2, \quad \ldots, \quad a_n = 2^{n-1} \] 2. **Calculate the sum of products taken two at a time**: The sum of the products taken two at a time can be expressed as: \[ S = a_1 a_2 + a_1 a_3 + a_1 a_4 + \ldots + a_{n-1} a_n \] This can be simplified to: \[ S = 1 \cdot 2 + 1 \cdot 2^2 + 1 \cdot 2^3 + \ldots + 1 \cdot 2^{n-1} + 2 \cdot 2^2 + 2 \cdot 2^3 + \ldots + 2^{n-2} \cdot 2^{n-1} \] 3. **Rearranging the terms**: We can group the terms based on the powers of 2: \[ S = \sum_{i=1}^{n-1} 2^i + \sum_{i=2}^{n-1} 2^{2i-1} \] 4. **Calculate the first sum**: The first sum is a geometric series: \[ \sum_{i=1}^{n-1} 2^i = 2 + 2^2 + 2^3 + \ldots + 2^{n-1} = 2(1 + 2 + 2^2 + \ldots + 2^{n-2}) = 2 \cdot \frac{2^{n-1} - 1}{2 - 1} = 2^{n} - 2 \] 5. **Calculate the second sum**: The second sum can also be simplified: \[ \sum_{i=2}^{n-1} 2^{2i-1} = 2^3 + 2^5 + \ldots + 2^{2(n-1)-1} = 2^3(1 + 2^2 + 2^4 + \ldots + 2^{2(n-3)}) = 2^3 \cdot \frac{2^{2(n-3)+2} - 1}{2^2 - 1} = \frac{2^{2n-2} - 8}{3} \] 6. **Combine the sums**: Now combine both sums: \[ S = (2^n - 2) + \frac{2^{2n-2} - 8}{3} \] Simplifying this gives: \[ S = \frac{3(2^n - 2) + 2^{2n-2} - 8}{3} = \frac{2^{2n-2} + 3 \cdot 2^n - 14}{3} \] 7. **Final expression**: The final expression can be simplified further, but we can check against the options given in the problem. ### Conclusion: After evaluating the sums and simplifying, we find that the answer does not match any of the provided options. Therefore, the answer is: **(d) none of these.**
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