Does there exist a geometric progression containing 27 and 8 and 12 as there of its terms ? If it exists, how many such progressions are possible?

Does there exist a geometric progression containing 27,8 and 12 as three of its term ? If it exists, then how many such progressions are possible ?

How many geometric progressions are possible containing 27, 8 and 12 as three of its/their terms

The first three terms of a geometric progression are 3, -1 and 1/3 . The next term of the progression is

The third term of a geometric progression is 4. Then find the product of the first five terms.

The first two terms of a geometric progression add up to 12. The sum of the third and the fourth terms is 48. If the terms of the geometric progression are alternately positive and negative, then the first term is

The first two terms of a geometric progression add up to 12. The sum of the third and the fourth terms is 48. If the terms of the geometric progression are alternately positive and negative, then the first term is

The first term of an arithmetic progression is 1 and the sum of the first nine terms equal to 369 . The first and the ninth term of a geometric progression coincide with the first and the ninth term of the arithmetic progression. Find the seventh term of the geometric progression.

The first term of an arithmetic progression is 1 and the sum of the first nine terms equal to 369 . The first and the ninth term of a geometric progression coincide with the first and the ninth term of the arithmetic progression. Find the seventh term of the geometric progression.

A geometric progression has common ratio = 3 and last term = 486. If the sum of its terms is 728, find its first term.

How many geometrical isomers are possible for