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For each `tinR," let "[t]` be the greatest integer less than or equal to t. Then `underset(xto0^(+))limx([(1)/(x)]+[(2)/(x)]+...+[(15)/(x)])`

A

is equal to 120

B

does not exist (in R)

C

is equal to 0

D

is equal to 15

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The correct Answer is:
A
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