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Let `f:""(-1,""1) rarr R` be a differentiable function with `f(0)""=""-1" "a n d" "f'(0)""=""1` . Let `g(x)""=""[f(2f(x)""+""2)]^2` . Then `g'(0)""=` (1) `-4` (2) 0 (3) `2` (4) 4

A

4

B

-4

C

0

D

-2

Text Solution

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The correct Answer is:
B
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VMC MODULES ENGLISH-DIFFERENTIAL CALCULUS-JEE main (Archive)
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