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Find the equation of the plane which is perpendicular to the plane `5x+3y+6\ z+8=0` and which contains the line of intersection of the planes `x+2y+3z-\ 4\ =\ 0\ a n d\ 2x+y\ -\ z+5\ =\ 0`

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The correct Answer is:
`51x + 15y - 50z + 173=0`
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VMC MODULES ENGLISH-THREE DIMENSIONAL GEOMETRY -JEE ADVANCED (ARCHIVE)
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  8. If the straight lines (x-1)/(2)=(y+1)/(k)=(z)/(2) and (z+1)/(5)=(y+1)/...

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  11. Perpendicular are drawn from points on the line (x+2)/(2)=(y+1)/(-1)=...

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  12. The equation of a plane passing through the line of intersection of th...

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  14. If the distance of the point P(1,-2,1) from the plane x+2y-2z=alpha,...

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  15. Equation of the plane containing the straight line (x)/(2)= (y)/(3)= (...

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  16. Consider three planes P(1):x-y+z=1, P(2):x+y-z=-1 and P(3):x-3y+3z=2...

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  17. Consider the planes 3x-6y-2z=15 and 2x+y-2z=5. Statement 1:The parame...

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  18. From a point P(lambda, lambda, lambda), perpendicular PQ and PR are dr...

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  19. Two lines L(1) : x=5, (y)/(3-alpha)=(z)/(-2) and L(2) : x=alpha, (y)/(...

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  20. A line l passing through the origin is perpendicular to the lines l(...

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  21. In R(3) , consider the planes P(1):y=0and P(2) : x+z=1. Let P(3) ...

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