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The equation of the plane containing the...

The equation of the plane containing the line
`vecr=hati+hatj+lamda(2hati+hatj+4hatk)` is

A

`vecr (-hati -2 hatj + hatk) =3`

B

`vecr (hati -4 hatj -hatk) =0`

C

`vecr (hati + 2 hatj -hatk)=3`

D

None of these

Text Solution

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The correct Answer is:
B
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The length of the perpendicular drawn from the point (2, 1, 4) to the plane containing the lines r=(hati+hatj)+lambda(hati+2hatj-hatk)" and "r=(hati+hatj)+mu(-hati+hatj-2hatk) is

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Find the vector equation of the following planes in cartesian form : " "vecr=hati-hatj+lamda(hati+hatj+hatk)+mu(hati-2hatj+3hatk) .

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VMC MODULES ENGLISH-THREE DIMENSIONAL GEOMETRY -LEVEL-1
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