The `IE_1 " and " IE_2` of Mg (g) are 740 and `1450 kJ "mol:^(-1)` . Calculate the percentage of `Mg^(+)` (g) and `Mg^(2+)` (g) if 1g of Mg (g) absorbs 50 kJ of energy.

Explanation

To solve the problem, we need to calculate the percentage of Mg⁺ and Mg²⁺ ions formed when 1g of magnesium (Mg) absorbs 50 kJ of energy. We will use the provided ionization energies (IE) for the calculations.

### Step-by-Step Solution:

1. **Calculate the number of moles of magnesium (Mg) in 1g:**
\[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} = \frac{1 \text{ g}}{24 \text{ g/mol}} = \frac{1}{24} \text{ mol} \approx 0.04167 \text{ mol} \]
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