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In the following, the element with the h...

In the following, the element with the highest ionization energy is

A

`[Ne]3s^(2)3p^1`

B

`[Ne]3s^(2)3p^3`

C

`[Ne]3s^(2)3p^(2)`

D

`[Ar]3d^(10)4s^(2)4p^2`

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The correct Answer is:
To determine which element has the highest ionization energy among the given options, we will analyze the electronic configurations of the elements in question and their stability. ### Step-by-Step Solution: 1. **Identify the Elements and Their Electronic Configurations:** - **Option A**: Neon (Ne) - Configuration: \(1s^2 2s^2 2p^6\) (Noble gas, fully filled) - **Option B**: Arsenic (As) - Configuration: \( [Ne] 3s^2 3p^3 \) (Half-filled p subshell) - **Option C**: Silicon (Si) - Configuration: \( [Ne] 3s^2 3p^2 \) (Not half-filled or fully filled) - **Option D**: Germanium (Ge) - Configuration: \( [Ar] 3d^{10} 4s^2 4p^2 \) (Not half-filled or fully filled) 2. **Analyze the Stability of Each Configuration:** - **Neon (A)**: Being a noble gas, it has a fully filled outer shell, which makes it very stable. However, ionization energy is not exceptionally high compared to other configurations. - **Arsenic (B)**: It has a half-filled p subshell (3p^3), which is exceptionally stable due to exchange energy and symmetry. This stability means it requires significantly more energy to remove an electron. - **Silicon (C)**: With the configuration \(3s^2 3p^2\), it does not have a half-filled or fully filled subshell, so it can ionize more easily than arsenic. - **Germanium (D)**: Similar to silicon, it has \(4s^2 4p^2\) and does not have a half-filled or fully filled subshell, making it less stable than arsenic. 3. **Compare Ionization Energies:** - The element with a half-filled p subshell (Arsenic) is expected to have the highest ionization energy due to its extra stability. - Neon, while stable, does not exhibit the same level of ionization energy as arsenic in this context. - Silicon and Germanium have lower ionization energies due to their configurations. 4. **Conclusion:** - Among the options, **Option B (Arsenic)** has the highest ionization energy due to its half-filled p subshell configuration, which provides extra stability. ### Final Answer: The element with the highest ionization energy is **Option B (Arsenic)**.

To determine which element has the highest ionization energy among the given options, we will analyze the electronic configurations of the elements in question and their stability. ### Step-by-Step Solution: 1. **Identify the Elements and Their Electronic Configurations:** - **Option A**: Neon (Ne) - Configuration: \(1s^2 2s^2 2p^6\) (Noble gas, fully filled) - **Option B**: Arsenic (As) - Configuration: \( [Ne] 3s^2 3p^3 \) (Half-filled p subshell) - **Option C**: Silicon (Si) - Configuration: \( [Ne] 3s^2 3p^2 \) (Not half-filled or fully filled) ...
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VMC MODULES ENGLISH-CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES -LEVEL -1
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