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Which of the following elements will not...

Which of the following elements will not show the inert-pair effect ?

A

Sn

B

Fe

C

Pb

D

In

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The correct Answer is:
To determine which of the following elements will not show the inert-pair effect, we first need to understand what the inert-pair effect is and the conditions under which it occurs. ### Step-by-Step Solution: 1. **Understanding Inert Pair Effect**: - The inert pair effect refers to the phenomenon where the outermost s-electrons (in the valence shell) of heavier elements become less reactive and do not participate in bonding. This is primarily due to the poor shielding of the s-electrons by the inner d and f electrons. 2. **Conditions for Inert Pair Effect**: - The inert pair effect is observed in elements that have d or f electrons in their electron configuration. The poor shielding by these inner electrons leads to a stronger attraction between the nucleus and the outermost s-electrons, causing them to remain unreactive. 3. **Identifying the Elements**: - The elements provided in the question include: - Tin (Sn) - Indium (In) - Lead (Pb) - Iron (Fe) 4. **Analyzing Each Element**: - **Tin (Sn)**: - Electron configuration: [Kr] 5s² 4d¹⁰ - Tin has d-electrons and can exhibit the inert pair effect. - **Indium (In)**: - Electron configuration: [Kr] 5s² 4d¹⁰ 5p¹ - Indium has d-electrons and can exhibit the inert pair effect. - **Lead (Pb)**: - Electron configuration: [Xe] 6s² 4f¹⁴ 5d¹⁰ 6p² - Lead has f-electrons and can exhibit the inert pair effect. - **Iron (Fe)**: - Electron configuration: [Ar] 4s² 3d⁶ - Iron does not have d or f electrons in the outermost shell that would lead to poor shielding, thus it does not show the inert pair effect. 5. **Conclusion**: - Among the elements listed, **Iron (Fe)** will not show the inert-pair effect because it lacks the necessary d or f electrons that would cause poor shielding. ### Final Answer: **Iron (Fe)** will not show the inert-pair effect.

To determine which of the following elements will not show the inert-pair effect, we first need to understand what the inert-pair effect is and the conditions under which it occurs. ### Step-by-Step Solution: 1. **Understanding Inert Pair Effect**: - The inert pair effect refers to the phenomenon where the outermost s-electrons (in the valence shell) of heavier elements become less reactive and do not participate in bonding. This is primarily due to the poor shielding of the s-electrons by the inner d and f electrons. 2. **Conditions for Inert Pair Effect**: ...
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VMC MODULES ENGLISH-CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES -LEVEL -1
  1. Consider the first ionization energies of the elements whose electroni...

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  2. Which of the elements whose atomic numbers are given below, cannot be ...

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  3. Which of the following elements will not show the inert-pair effect ?

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  4. Which of the following arrangements shows the correct order of increas...

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  5. The element having the electronic configuration 1s^(2) 2s^(2) 2p^(6) 3...

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  6. In the periodic table ,with the increase in atomic number , the metall...

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  7. Which of the following molecules is isoelectronic with N2O ?

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  8. The atomic radius of elements of which of the following series would b...

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  9. Which of the following contains an 18-electron structure ?

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  10. Which of the following transformations is considered in defining ioniz...

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  11. In which of the following properties is periodicity not exhibited by t...

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  12. The first ionization energy of Ar is less than that of Ne. An explanat...

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  13. According to the periodic law of elements, the variation in properties...

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  14. Which one of the following group represents a collection of isoelectro...

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  15. Which of the following elements never has an oxidation state +1?

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  16. The fourth period of modern periodic table includes:

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  17. The ionisation potential is lowest for the

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  18. An element with high electronegativity has:

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  19. Which of the following elements has maximum electronegativity?

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  20. The paramagnetic species among the following is- Na^(+), Zn^(2+), Cu^(...

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