EN of the element (A) is `E_(1)` and IP is `E_(2)`. Then EA will be

Options

A. `2E_1 - E_2`
B. `E_1 - E_2`
C. `E_1 - 2E_2`
D. `(E_1 + E_2)//2`

Explanation

To find the electron affinity (EA) of the element (A) given its electronegativity (EN) as \( E_1 \) and ionization potential (IP) as \( E_2 \), we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Definitions**:
- **Electronegativity (EN)**: This is a measure of the tendency of an atom to attract a bonding pair of electrons. In this case, it is given as \( E_1 \).
- **Ionization Potential (IP)**: This is the minimum amount of energy required to remove an electron from the outermost shell of an isolated gaseous atom, given as \( E_2 \).
- **Electron Affinity (EA)**: This is the change in energy when an electron is added to an atom to form a negative ion.

2. **Using the Mulliken Scale**:
- According to the Mulliken scale, the electronegativity (EN) can be expressed as the average of the ionization potential (IP) and electron affinity (EA):
\[ EN = \frac{IP + EA}{2} \]
- Substituting the known values:
\[ E_1 = \frac{E_2 + EA}{2} \]

3. **Rearranging the Equation**:
- To isolate EA, we can rearrange the equation:
\[ 2E_1 = E_2 + EA \]
- Now, subtract \( E_2 \) from both sides:
\[ EA = 2E_1 - E_2 \]

4. **Final Expression**:
- Thus, the expression for electron affinity (EA) in terms of electronegativity (EN) and ionization potential (IP) is:
\[ EA = 2E_1 - E_2 \]

### Conclusion:
The electron affinity (EA) of the element (A) is given by the formula:
\[ EA = 2E_1 - E_2 \]