On moving from Li to F in the second period, there would be a decrease in:

Options

A. non-metallic property
B. atomic radius
C. ionization potential
D. electronegativity

Explanation

To solve the question "On moving from Li to F in the second period, there would be a decrease in:", we need to analyze the trends in the periodic table as we move from lithium (Li) to fluorine (F).

### Step-by-Step Solution:

1. **Identify the Elements**:
- We are moving from Lithium (Li) to Fluorine (F) in the second period of the periodic table.

2. **Understand the Trend**:
- As we move from left to right in a period, several properties change due to the increasing atomic number and the corresponding increase in the positive charge of the nucleus.

3. **Analyze Atomic Radius**:
- The atomic radius generally **decreases** from left to right across a period. This is because the increasing nuclear charge pulls the electrons closer to the nucleus, resulting in a smaller atomic size.

4. **Consider Non-metallic Character**:
- The non-metallic character **increases** from Li to F. This is not what we are looking for since we need a property that decreases.

5. **Ionization Energy**:
- Ionization energy tends to **increase** from Li to F. This means it becomes harder to remove an electron as we move from left to right.

6. **Electronegativity**:
- Electronegativity also **increases** from Li to F. Fluorine is one of the most electronegative elements.

7. **Conclusion**:
- The only property that decreases when moving from Li to F is the **atomic radius**. Therefore, the correct answer to the question is that there would be a decrease in atomic radius.

### Final Answer:
On moving from Li to F in the second period, there would be a decrease in **atomic radius**.

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