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The arrangement of X^(ɵ) ions around A^(...

The arrangement of `X^(ɵ)` ions around `A^(o+)` ion in solid `AX` is given in the figure (not drawn to scale). If the radius of `X^(ɵ)` is `250 pm`, the radius of `A^(o+)` is

A

104 pm

B

125 pm

C

183 pm

D

57 pm

Text Solution

Verified by Experts

Using radius ratio for octahedral void (FCC)
`(r^(+))/(r^(-)) = 0.414 " " therefore " " r^(+) = 0.414 xx 250 = 104`
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