The equation of a projectile is `y=sqrt(3)x-(gx^(2))/(2)`
the angle of projection is:-

Options

A. `pi/6`
B. `pi/3`
C. `pi/2`
D. zero

Explanation

To find the angle of projection from the given equation of a projectile, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Equation**:
The equation of the projectile is given as:
\[ y = \sqrt{3}x - \frac{g}{2}x^2 \]

2. **Recognize the General Form of the Projectile's Equation**:
The general equation of the trajectory of a projectile can be expressed as:
\[ y = x \tan \theta - \frac{g}{2u^2 \cos^2 \theta} x^2 \]
where \( \theta \) is the angle of projection.

3. **Compare the Two Equations**:
By comparing the coefficients of \( x \) and \( x^2 \) from the given equation and the general form, we can identify:
- The coefficient of \( x \) in the given equation is \( \sqrt{3} \).
- The coefficient of \( x \) in the general form is \( \tan \theta \).

4. **Set Up the Equation**:
From the comparison, we have:
\[ \tan \theta = \sqrt{3} \]

5. **Find the Angle \( \theta \)**:
To find \( \theta \), we take the arctangent of both sides:
\[ \theta = \tan^{-1}(\sqrt{3}) \]
We know that:
\[ \tan 60^\circ = \sqrt{3} \]
Therefore:
\[ \theta = 60^\circ \]

6. **Convert to Radians (if necessary)**:
If required, we can convert degrees to radians:
\[ \theta = \frac{\pi}{3} \text{ radians} \]

### Final Answer:
The angle of projection is:
\[ \theta = 60^\circ \text{ or } \frac{\pi}{3} \text{ radians} \]