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Two particles, one of mass m and the other of mass 2m, are projected horizontally towards each other from the same level above the ground with velocities 10 m/s and 5 m/s, respectively. They collide in air and stick to each other. The distance of the combined mass from point A is

A

(a)40 m

B

(b)20 m

C

(c)30 m

D

(d)zero

Text Solution

Verified by Experts

The correct Answer is:
A

They will fall through the same height say h. Let them collide at a distance x from tower A.
`therefore h=1/2 gt^(2) ........(i)`
`x=5t .......(ii)`
`60-x=10t ...........(iii)`
Solving (ii) and (iii) we get x=20m, t=4 sec, h=89m
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