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The time of flight of the projectile is:...

The time of flight of the projectile is:

A

`asqrt(2/(bg))`

B

`a/sqrt(bg)`

C

`sqrt((2a)/(bg))`

D

`sqrt(a/(2bg))`

Text Solution

Verified by Experts

The correct Answer is:
A
`T=2 sqrt((2H)/(g))=2 sqrt((2a^(2))/(4bg))=asqrt((2)/(bg))`
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