A projectile attains a certain maximum height H1 when projected from earth. If it is projected at the same angle and with the same initial speed from the moon, where the acceleration due to gravity is one-sixth that on earth, the maximum height attended by the projectile is `H_2`. THe ratio `H_2//H_1` is:

Explanation

To solve the problem, we need to find the ratio of the maximum heights attained by a projectile when launched from Earth and the Moon. Let's denote:

- \( H_1 \) as the maximum height attained on Earth.
- \( H_2 \) as the maximum height attained on the Moon.
- \( g_E \) as the acceleration due to gravity on Earth.
- \( g_M \) as the acceleration due to gravity on the Moon.

Given that \( g_M = \frac{1}{6} g_E \), we can use the formula for the maximum height of a projectile, which is given by:
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